Question

the price of a bat and ball is rs 600. price of three balls and one bat is rs 760.find the price of bat and ball.​

Answer 1

Step-by-step explanation:

ANSWER:-

Concept:-

• Let the price of bat be x.
• Let the price of ball be y.

Let's Do!

$x + y = 600$

$3y + x = 760$

Subtracting both equations,

$3y + x - (x + y) = 760 - 600$

$3y + x - x - y = 160$

$3y - y = 160$

$2y = 160$

$y = 80$

So, price of one ball is 80.

$x + y = 600$

$x + 80 = 600$

$x = 600-80$

$x = 520$

And price of one bat is 520.

Answer 2

$\huge\bf{\underline{\underline{\red{Answer:}}}}$

$\large\Rightarrow{\boxed{\sf{\orange{Price\:of\:one\:bat\:is\:520.}}}}$

$\large\Rightarrow{\boxed{\sf{\orange{Price\:of\:one\:ball\:is\:80.}}}}$

$\huge\bf{\underline{\underline{\purple{Explanation:}}}}$

Let the price one ball and bat be a and b.

According to the question,

:$\implies{\sf{a+b = 600\:\:\:\:....(1)}}$

:$\implies{\sf{3a+b= 760\:\:\:\:....(2)}}$

Subtracting (2) from (1),

:$\implies{\sf{(3a+b)-(b+a)=760-600}}$

:$\implies{\sf{(3a+b - b - a)=760-600}}$

:$\implies{\sf{(3a- a)=760-600}}$

:$\implies{\sf{(2a)=160}}$

:$\implies{\sf{a= \dfrac{160}{2}}}$

:$\implies{\sf{a= 80}}$

$\large{\underline{\sf{\pink{Therefore,\:the\:Price\:of\:one\:ball\:is\:80.}}}}$

If a = 80, then,

:$\Rightarrow{\sf{a+b=600}}$

:$\Rightarrow{\sf{80+b=600}}$

:$\Rightarrow{\sf{b=600-80 = 520}}$

:$\Rightarrow{\sf{b=520}}$

$\large{\underline{\sf{\pink{Therefore,\:the\:Price\:of\:one\:bat\:is\:520.}}}}$

$\rule{400}4$