the price of a car lowered by 20% to rupees 40000 what is the original price also find the reduction in price
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Answered by
34
x-20/100×x=40000
100x-20x/100=40000
80x/100=40000
x=40000×100/80
x=50000 is the original price
50000-40000=10000 is the reduction
100x-20x/100=40000
80x/100=40000
x=40000×100/80
x=50000 is the original price
50000-40000=10000 is the reduction
Answered by
3
20%of x =40000
x=40000×100/20
x=200000
reduced=200000-40000=160000
x=40000×100/20
x=200000
reduced=200000-40000=160000
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