Question

The price of a car was ₹3,46,000. It has decreased by 20% this year. What is the price now?​

Answer 1

Answer:

Given that price of scooter last year was = Rs. 34,000

20% of 34,000 =

100

34000×20

=6800

Now, price of scooter after increased 20% =34000+6800 = Rs. 40,800

Hence, this is the answer.

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Answer 2

Given :

• Price of Car = ₹ 3,46,000
• Dreased by = 20 %

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To Find :

• Current Price = ?

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Solution :

~ Formula Used :

$\large{\red{\dashrightarrow}} \: \: {\underline{\boxed{\purple{\sf{ C.I = P \bigg[1 + \dfrac{R}{100} \bigg]^T - P }}}}}$

Where :

• C.I = Decreased Amount
• P = Price of Car
• R = Decreased %
• T = Time

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~ Calculating the Current Cost :

${:\implies{\qquad{\sf{ C.I = P \bigg[1 + \dfrac{R}{100} \bigg]^T - P }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 346000 \bigg[1 + \dfrac{20}{100}\bigg]^1 - 346000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 346000 \bigg[1 + \dfrac{20}{100} \bigg]^1 - 346000 }}}} \\ \\ \ {:\implies{\qquad{\sf{C.I = 346000 \bigg[1 + \cancel\dfrac{20}{100} \bigg]^1 - 346000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 346000 \bigg[1 + 0.20 \bigg]^1 - 346000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 346000 \bigg[1.20 \bigg]^1 - 346000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 346000 \times 1.20 - 346000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 415200 - 346000 }}}} \\ \\ \ {\qquad{\sf{ Price \: decrease \: on \: the \: car \: = {\green{\sf{ ₹ \: 69200 }}}}}}$

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~ Calculating the Current Amount :

${\longmapsto{\qquad{\sf{ Current \: Amount \: = Price \: of \: Car - Depreciation \: Amount }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ Current \: Amount \: = 346000 - 69200 }}}} \\ \\ \ {\qquad{\textsf{ Current Price of the car = {\pink{\sf{ ₹ \: 276800 }}}}}}$

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Therefore :

❝ Current price of the Car is ₹ 276800 .❞

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