Question

The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ linked with the primary coil is given by ϕ=ϕ0+4t, where ϕ is in webers, t is time in seconds and ϕ0 is a constant, the output voltage across the secondary coil is :

Answer 1

The answer to the question:  The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ linked with the primary coil is given by ϕ=ϕ0+4t, where ϕ is in Weber’s, t is time in seconds and ϕ0 is a constant, the output voltage across the secondary coil is going to be 120 V.

Answer 2

Answer:

The output voltage across the secondary coil is 120V

Explanation:

Let assume that the voltage across the primary coil is Vp and voltage across the secondary coil is Vs.

Given the transformer has Np turns at primary coil and Ns turns at the secondary coil.

Where, Np=50 turns and Ns=1500 turns.

The magnetic flux φ is linked with the primary coil. So magnetic flux φ= φ0+4t webers.

So the voltage across the primary coil is

Vp=dφ/dt

=> Vp=d(φ0+4t)/dt

∴Vp=4V

Now the voltage across the secondary coil is

Vs/Vp=Ns/Np

=> Vs= (1500x4)/50

∴Vs =120v