Question

The primary unbalanced force is maximum when the angle of inclination of the crank with the line of stroke is

Answer 1

The primary unbalanced force is maximum, when θ = 0° or 180°. Thus, the primary force is maximum twice in one revolution of the crank. The maximum primary unbalanced force is given by
FP(max) = m⋅ω2⋅r

Answer 2

Max angle of Inclination is:  θ = 0° or 180°

Explanation:

• The primary unbalanced force is always maximum when the angle θ = 0° or 180°.

• primary force is maximum, twice in one revolution of crank. The maximum primary unbalanced force is written as:

             FP(max) = m⋅ω2⋅r

• Due to partial balance of the reciprocating part, there are the unbalanced primary force along line of stroke and also the unbalanced primary force perpendicular to line of stroke.

• Unbalanced force due to reciprocal mass varies in magnitude but it is constant in a direction while due to the revolving masses, the unbalanced force is constant in magnitude but varies in a direction.

• The expression (m. ω2. r cos θ) is called the primary unbalanced force and is known as the secondary unbalanced force.

Therefore solution is : θ = 0° or 180°

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