The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4. this distribution takes only whole-number values, so it is certainly not a normal distribution. let "x-bar" be the mean number of accidents per week at the intersection during a year (52 weeks). what is the approximate probability that there are fewer than 100 accidents in a year? (hint: restate this event in terms of "x-bar")
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130 per year = 130/52 = 2.5 per week
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(2.5-2.2)/1.4 = 1.78
So an average of 2.5 accidents perweek is 1.78 standard deviations
above the mean of 2.2.
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The appromate chance the average is less than 2.5 accidents per week
is about 96% or 0.9629...
I hope the answer was helpful to you If it was please mark it as brainlist ❤️
----
(2.5-2.2)/1.4 = 1.78
So an average of 2.5 accidents perweek is 1.78 standard deviations
above the mean of 2.2.
-----
The appromate chance the average is less than 2.5 accidents per week
is about 96% or 0.9629...
I hope the answer was helpful to you If it was please mark it as brainlist ❤️
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