Question

The probabilities of solving a mathematical problem by A B. C are 1/2, 1/3, 1/4 respectively. Find the probability of not solving the problem

Answer 1

subtract all from 1 u wil get ans

Answer 2

Hey there !!

Here we have

$The \: \: probabilities \: \: of solving \: \: a \: \: \: \: mathematical \: \: \\ problem \: \: By \: \: A \: \: is \: = \frac{1}{2} \: \\ \\ \\ The \: probabilities \: of \: solving \: a \: mathematical \: \: problem \: \: \: By \: B \: is \: = \frac{1}{3} \\ \\ and \: similarly \: for \: C \: is \: \: = \frac{1}{4}$

We know that , Probability of not happening of an event , P ( Not ) = 1 - P ( E)

Now , proceeding with this we get

$P ( \: Not \: \: solving \: \: by \: \: A \: \: ) \: \: = 1 - \frac{1}{2} \\ \\ = \frac{2 - 1}{2} \\ \\ = \frac{1}{2} \\ \\ P ( \: Not \: \: solving \: \: by \: \: B \: \: \: ) \: \: \: = 1 - \frac{1}{3} \\ \\ = \frac{3 - 1}{3} \\ \\ = \frac{2}{3} \\ \: \\ P ( \: Not \: \: solving \: \: by \: \: c \: \: \: ) \: \: = 1 - \frac{1}{4} \\ \\ = \frac{4 - 1}{4} \\ \\ = \frac{3}{4}$

Hence The probability P ( Not solving by A , B , C ) = 1 /2 , 2/3 , 3/ 4



Hope this would help you !!