Question

the probability of the union of two mutually exclusive event A abd B , given that P(A) is 0.3 and p(B) is 0.4

#0
#0.1
#0 7
#0.12​

Answer 1

Answer:

Answer :- is # 0.7 .

Step-by-step explanation:

p(A or B ) =p(A) + p(B) - p( A and B )

if they are independent, then p(A and B) = p (A) . p ( B) , so

p ( A or B ) = 0.3 + 0.4 - 0.0 = 0.7

I hope this answer is helpful.