The probability os selecting a red ball at random from a jar that contain only red,blue and orange is 1/4.The probabilty of selecting a blue ball at random from the same jar is 1/3.If the jar contain 10 orange ball .Find the total no of ball in thr jar
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let total no of balls be x
then - no. of red balls = x*[1/4]
no. of blue balls = x*[1/3]
no . of orange balls = 10 [given]
so x = x[1/4] +x[1/3] + 10
= x/4 + x/3 +10
=[3x + 4x]/12 +10
= 7x / 12 +10
x =[7x + 120]12
[12] x = 7x +120
12x = 7x + 120
12x -7x =120
5x =120
x =120/5
x =24
so total balls =24 (ANS).
hopes this helps!!!!!!!!!
then - no. of red balls = x*[1/4]
no. of blue balls = x*[1/3]
no . of orange balls = 10 [given]
so x = x[1/4] +x[1/3] + 10
= x/4 + x/3 +10
=[3x + 4x]/12 +10
= 7x / 12 +10
x =[7x + 120]12
[12] x = 7x +120
12x = 7x + 120
12x -7x =120
5x =120
x =120/5
x =24
so total balls =24 (ANS).
hopes this helps!!!!!!!!!
Answered by
0
let total no of balls be x
then
no. of red balls = x*[1/4]
no. of blue balls = x*[1/3]
no . of orange balls = 10 [given]
so
x = x[1/4] +x[1/3] + 10
= x/4 + x/3 +10
=[3x + 4x]/12 +10
= 7x / 12 +10
x =[7x + 120]12
[12] x = 7x +120
12x = 7x + 120
12x -7x =120
5x =120
x =120/5
x =24
so total balls =24
Hope it helps
Pls mark it the brainliest
then
no. of red balls = x*[1/4]
no. of blue balls = x*[1/3]
no . of orange balls = 10 [given]
so
x = x[1/4] +x[1/3] + 10
= x/4 + x/3 +10
=[3x + 4x]/12 +10
= 7x / 12 +10
x =[7x + 120]12
[12] x = 7x +120
12x = 7x + 120
12x -7x =120
5x =120
x =120/5
x =24
so total balls =24
Hope it helps
Pls mark it the brainliest
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