Question

The probability that a candidate can pass in an exam is 0.6i)What is the probability that he pass in the third trial?ii)What is the probability that he pass before the third trial.​

Answer 1

14

45

Explanation:

P(A or B) = P(A) + P(B) - P(A and B)

Take

A = Mr x passes Mathematics

B = Mr x passes Statistics

Then we have

P(A or B) = 4/5 = 2/3 + 4/9 - P(A and B)

⇒

P(A and B) = 2/3 + 4/9 - 4/5

=

30

+

20

−

36

45

=

14

45