The probability that a candidate can pass in an exam is 0.6i)What is the probability that he pass in the third trial?ii)What is the probability that he pass before the third trial.
Answers
Answered by
3
14
45
Explanation:
P(A or B) = P(A) + P(B) - P(A and B)
Take
A = Mr x passes Mathematics
B = Mr x passes Statistics
Then we have
P(A or B) = 4/5 = 2/3 + 4/9 - P(A and B)
⇒
P(A and B) = 2/3 + 4/9 - 4/5
=
30
+
20
−
36
45
=
14
45
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