Math, asked by brenda559, 1 month ago

The probability to have exactly 52 fridays in a non-leap year is​

Answers

Answered by Anonymous
4

Answer:

The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcomes or elements of a sample space is 7. 6/7 or 0.86 is probability for 52 Mondays in a non-leap year.

Step-by-step explanation:

Answered by Anonymous
11

Answer:

6/7

Step-by-step explanation:

A non-leap year has 365 days .

A year has 52 weeks. Hence there will be 52 Sundays for sure.

52 weeks = 52 x 7 = 364 days .

365– 364 = 1 day extra.

In a non-leap year, there will be 52 Sundays and 1 day will be left.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Of these total 7 outcomes, the favorable outcomes are 1.

Hence the probability of getting 53 Sundays = 1 / 7.

∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7.

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