Question

The product of additive inverses of (x^(2)-1)/(2x) and (x^(2)-4)/(3-x) is (a) x^(2)+5x+6 (b) x^(2)+x-6 (c) x^(2)-x-6 (d) x^(2)-5x+6

Answer 1

Step-by-step explanation:

x^2 - 4 / 3 -x

additive inverse of x^2 - 1 / 2x = - 2x / x^2 - 1

- 2x / x^2 - 1 * x^2 - 4 / 3 -x = -2x ( x^2 - 4 ) / x^2-1 (3-x )

= -2x^3 + 8 / 3x^2 -3 - x^3 +x