The product of four consecutive natural numbers
is 840. Find the numbers.
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Answer:
Acordingly:-
(x-2).(x-1) .x.(x+1) = 840
(x^2–2x)×(x^2–1)= 840
x^4–2x^3-x^2+2x-840 = 0
On putting x=6
R=1296–432–36+12–840=1308–1308=0
(x-6)is a factor
x^4–2x^3-x^2+2x-840=0
x^3(x-6)+4x^2(x-6)+23x(x-6)+140(x-6)=0
(x-6)(x^3+4x^2+23x+140) =0
Euther x-6=0 => x =6
1st number =x-2 =6–2 = 4
2nd number =x-1=6–1 = 5
3rd number =x = 6
4th number =x+1 =6+1 = 7
4 numbers are 4 , 5 , 6 and 7
Explanation:
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