Question

The product of the zeroes of xcube + 4xsquare+x-16

Answer 1

★ Given that,

Find the product of the zeroes of polynomial

$\tt\:p(x) = x^{3} + 4x^{2} + x - 16$

★ Let,

• a = 1
• b = 4
• c = 1
• d = - 16

$\tt\:⟹ \alpha + \beta + \gamma = \frac{-b}{a} = \frac{-4}{1} = - 4$

$\tt\:⟹ \alpha\beta + \beta\gamma + \alpha\gamma = \frac{c}{a} = \frac{1}{1} = 1$

$\tt\:⟹ \alpha\beta\gamma = \frac{-d}{a} = \frac{-(-16)}{1} = 16$

Hence,it is solved...

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