Math, asked by nikhilbattineni, 8 months ago

the profit function p(x) for a company,selling x items per day is given p(x)=(150-x)x-1600
Find number of items company should sell for maximum profit.also find the maximum profit

Answers

Answered by amitnrw
2

Given : profit function p(x) for a company, selling x items per day is given p(x)=(150-x)x-1600  

To Find : number of items company should sell for maximum profit

maximum profit

Solution:

p(x)=(150-x)x-1600  

p'(x) = (150- x)  + (-1)x  - 0

=> p'(x) =  150- x - x

=> p'(x) =  150- 2x

p'(x) = 0

=> 150- 2x = 0

=> x = 75

p'(x) =  150- 2x

p''(x) = - 2 < 0

Hence maximum profit at x = 75

Profit = (150-x)x-1600  

= (150 - 75)75 - 1600

= 4025

number of items company should sell for maximum profit  = 75

maximum profit  = 4025

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Answered by gaminggopichand
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