Question

the proportion of caf2 in a sample of water is 156ppm what will be molarity​

Answer 1

Answer:

The concentration of chloroform=15 ppm

∴ 10^6 g of solution contains 15 g chloroform

Thus, 1000g of solution contains  

10  

6

 

15

​  

×1000=15×10  

−3

g chloroform

Molality=  

mass of solvent(kg)

number of moles of solute

​  

 

and number of moles =  

molar mass

mass

​  

 

For chloroform, CHCl  

3

​  

 

mass=15×10  

−3

g,  

molar mass=12+1+3×35.5=119.5g/mol

Weight of water = 1000g = 1 kg

Molality =  

119.5×1

15×10  

−3

 

​  

=1.25×10  

−4

 m