Question

The question is the pic attached ​

Answer 1

Answer:

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Step-by-step explanation:

so here triangle pqs is congruent to triangle prt

so hence

pq=pt (1)

pr=ps (2) (c.s.c.t)

so dividing these both equations

we get

pq/pr=pt/ts

now applying alternendo

we get

pq/pt=pr/ts (3)

now considering triangles pqr and pts

angle qpr=angle spt (vertically opp.angles)

also pq/pt=pr/ts (from (3))

hence triangle pqr is similar to triangle pts by S.A.S Test

thus proved