Question

The radii of two circular ends of a frustum of a cone shaped dustbin are 15 and 8. if its depth is 63cm, find the volume of the dustbin​

Answer 1

Given the height or depth of the container (h)= 63cm

Radius of the upper end =$r_{1}$

Radius of the lower end =$r_{2}$

The shape of the bucket is frustum.

Volume of the frustum = $\frac{1}{3} \pi * (r_{2}*r_{1} *r_{1} r_{2} )*h$

volume of dustbin = $\frac{1}{3} * \frac{22}{7}*(15^{2}+15*8+8^{2} )*63$

                              = $\frac{1}{3} * \frac{22}{7}*(225+120+64 )*63$

                              =$\frac{1}{3}*\frac{22}{7} * 409*63$

                              =26994$cm^{3}$

therefore the volume of dustbin is 26994$cm^{3}$

Answer 2

Answer:

upper answer is right

Step-by-step explanation:

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