The radii of two cyclinder are in the ratio 3:4 and their are in the ratio 5:3.find the ratio of their curved surface areas.
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5:4
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Given :
Radii of two cylinders are in the ratio 3:5 and there hight in the ratio of 5:3.
r1 = 3. h1 = 5
r2 = 4 h2 = 3
Ratio of their CSA = (CSA of cylinder1)/(CSA of cylinder2)
Ratio of their CSA = (2πr1h1)/(2πr2h2)
Ratio of their CSA = (r1h1)/(r2h2)
Ratio of their CSA = (3×5)/(4×3)
Ratio of their CSA = 5/4
Therefore, the ratio of their CSA are 5:4
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