the radius and height of a right circular cylinder are each increased by 20%. what percentage increases is in the volume?
Answers
Answered by
11
Answer =72.80%
volume =πr^2h
new radius =r+20/100r=6/5r
so
=h+20/100h=6/5h
v=π (6/5)^2 (6/5h)=216/125πr^2h
therefore increase volume
91/125πr^2h
therefore 72.80%
volume =πr^2h
new radius =r+20/100r=6/5r
so
=h+20/100h=6/5h
v=π (6/5)^2 (6/5h)=216/125πr^2h
therefore increase volume
91/125πr^2h
therefore 72.80%
Answered by
1
r = r+20\100=r+1\5
h = h+20\100=h+1\5
v=πr^2h
v=πr^2+1\25×h+1\25
v=1\25(πr^2h)
25v=(πr^2h)
Answer=25
h = h+20\100=h+1\5
v=πr^2h
v=πr^2+1\25×h+1\25
v=1\25(πr^2h)
25v=(πr^2h)
Answer=25
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