the radius of a circular is 35 metre on its outside there is a path 5 m wide find the cost of levelling the path at rupee 5.50 square metre
Answers
Answered by
61
Solution :
The radius of the circular field,
r = 35 m
Now, the area of the circular field
= πr² m²
= π * 35² m²
= 1225π m²
Given that, the width of the path is 5 m
Now, the radius of the circular field along with the path around it
= (radius of the circular field) + (width of the path)
= 35 + 5 m
= 40 m
So, the area of the of the circular field along with the path around it
= π (40)² m²
= 1600π m²
Thus, the area of the path
= (the area of the circular field along with the path around it) - (the area of the circular field) m²
= (1600π - 1225π) m²
= 375π m²
Thus, the cost of levelling the path at Rs 5.50 per m²
= Rs (5.50 * 375π)
= Rs (5.50 * 375 * 22 / 7)
= Rs 6482.14
Answered by
45
here is your answer
Given,
refer to the attachment for diagram
radius of circular path = 35m(OA)= r 1
radius of the outer path = (35+5) m
= 40m(OD) = r 2
Area of circle =πr^2
Now, area of the circular path
= >area of circle with radius OD-
area of circle with radius OA
=> π(r 2)^2 - π(r 1)^2
=> π {( r2)^2 - (r1)^2}
=> π{(40)^2 - (35)^2}
=>π( 1600- 1225)
=>π( 375) m^2
NOW,
cost of levelling per square meter path =
Rs5.50
hence, cost of levelling (375)π square meter path
=(375× 5.50×22)/7
=> Rs6482.142
Hence the total cost is Rs 6482.142 for labelling the path.
hope it helps
BE BRAINLY///
Given,
refer to the attachment for diagram
radius of circular path = 35m(OA)= r 1
radius of the outer path = (35+5) m
= 40m(OD) = r 2
Area of circle =πr^2
Now, area of the circular path
= >area of circle with radius OD-
area of circle with radius OA
=> π(r 2)^2 - π(r 1)^2
=> π {( r2)^2 - (r1)^2}
=> π{(40)^2 - (35)^2}
=>π( 1600- 1225)
=>π( 375) m^2
NOW,
cost of levelling per square meter path =
Rs5.50
hence, cost of levelling (375)π square meter path
=(375× 5.50×22)/7
=> Rs6482.142
Hence the total cost is Rs 6482.142 for labelling the path.
hope it helps
BE BRAINLY///
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SANJAILION:
nice
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