Question

the radius of a curvature of a convex mirror used on a moving automobile is 2.0m.A truck is coming behind it as a distance of 3.5m.Calculate

a)the position
b)the size of the image relative to the size of the truck.what will be the nature of the image?​

Answer 1

Hii ammu, here is d ans u asked fr;

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Given :

Given :R = 2 m=> focal length, f = R/2=> f = 1 mObject distance, u = -3.5 m

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To find :

To find :Position of the image, magnification and nature of the image.

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Solution :

Solution :1/v + 1/u = 1/f1/v = 1/f - 1/u1/v = 1/1 - 1/(-3.5)1/v = (3.5 + 1) / 3.51/v = 4.5 / 3.5v = 3.5 / 4.5v = 0.77 m

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Therefore, the image will be formed at a distance of 0.77 m from the mirror.

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Magnification, m = h'/h = - v/u

Magnification, m = h'/h = - v/um = - (0.77) / (-3.5)m = 0.77 / 3.5m = 0.22 m=> m < 1

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Therefore, the image will be diminished, virtual and erect. Hope this helps u!!Plzz mark me as BRAINLIEST..~$€❤