The radius of a sphere is 10 cm. If its radius is increased by 1 cm, then volume of the sphere is increased by
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Answered by
2
Answer:
Original volume = 4π10³/3 = 4000π/3
Increased volume = 4π11³/3 = 5324π/3
Subtracting original from increased volume,
We get: 5324π/3 - 4000π/3 = 1324π/3 cm³
Therefore, volume increased by 1324πcm³
Answered by
3
Answer:
V=4/3πr³
Step-by-step explanation:
V=4/3π10³
V=(4000π)/3
V'=4/3π11³
V'=(5324π)/3
∆V=V'-V
∆V=(1324π)/3
∆V=(1324×3.14)/3
∆V=(4157.36)/3
∆V=1385.78 cm²
Thus increase in volume is 1385.78cm²
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