The radius of a spherical metallic ball is 21 cm . It is melted and recast into a right conical funnel , the base of which is 28 cm in diameter . find the height of the conical funnel
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Radius of sphere = 21 cm
Volume of sphere = 4 pi r^3 / 3
= 4*22*21*21*21/ 7*3
= 88* 22*22
= 38808 cm^3
Now,
Radius of cone = 14 cm
Volume of cone = Volume of sphere
pi*r^2 *h / 3 = 38808
=> 22*14*14*h/7*3 = 38808
=> 88 *14 * h = 38808 * 3
=> 14h = 441 * 3
=> h = 63*3/2
=> h = 94.5 cm
Height of conical funnel = 94.5 cm
Hope it is correct and will help you
Please mark as brainliest if you liked the solution
Volume of sphere = 4 pi r^3 / 3
= 4*22*21*21*21/ 7*3
= 88* 22*22
= 38808 cm^3
Now,
Radius of cone = 14 cm
Volume of cone = Volume of sphere
pi*r^2 *h / 3 = 38808
=> 22*14*14*h/7*3 = 38808
=> 88 *14 * h = 38808 * 3
=> 14h = 441 * 3
=> h = 63*3/2
=> h = 94.5 cm
Height of conical funnel = 94.5 cm
Hope it is correct and will help you
Please mark as brainliest if you liked the solution
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