the radius of conducting wire is doubled.what will be the ratio of its new specific resistence to the old one?
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Resistance will become half because resistance is inversely promotional to the area of cross section. Ratio will be 1:2
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radius is inversely proportional to resistance. i.e, as radius increases, resistance decreases.
ratio of new resistance to old one= 1:4
ratio of new resistance to old one= 1:4
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