The radius of the cone is increased by 2.7% and its height is reduced by 0.9%.Determine the percentage change in its volume.
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The volume of a cone = 1/3πr²h
The change in radius is :
= 1.027r
The change in height :
= 0.991h
The change in volume is :
(1.027r)² × 0.991h = 1.045236r²h
1.045236r²h - r²h = 0.045236r²h
0.045236r²h/r²h = 0.045236
0.045236 × 100 = 4.5236%
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