the radius of the sphere is 10 cm if the radius is increased by 1 cm then prove that volume of the sphere is increased by 33%
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Atq, R 1 is 10 cm
R2 is 10+1= 11 cm
Vol of sphere is given by 4/3πr^3
so, 4/3 x 3.14 x 10 x 10 x 10
= 4188 cm cube
now, 2nd case when r is increased by 1 cm
4/3 x 3.14 x 11 x 11 x 11
= 5575 cm cube
now , 33% of 4188 is 4188 x 33 /100 which is 1382
if we subtract 4188 from 5575 we get almost same result which is 1386..
Hence proved
R2 is 10+1= 11 cm
Vol of sphere is given by 4/3πr^3
so, 4/3 x 3.14 x 10 x 10 x 10
= 4188 cm cube
now, 2nd case when r is increased by 1 cm
4/3 x 3.14 x 11 x 11 x 11
= 5575 cm cube
now , 33% of 4188 is 4188 x 33 /100 which is 1382
if we subtract 4188 from 5575 we get almost same result which is 1386..
Hence proved
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