the radius of two right circular cylinders are in the ratio 2:3 and their heights are in the ratio 5:4 then find the ratio of their curved surface areas?
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..QUESTION..
ㅤㅤㅤ
The radius of two right circular cylinders are in the ratio 2:3 and their heights are in the ratio 5:4 then find the ratio of their curved surface areas?
..ANSWER..
GIVEN ,
ㅤㅤㅤ➪ Ratio of radius = 2:3
ㅤㅤㅤ➪ Ratio of height = 5:4
★ Let all the values be x
•°• Ratio of Radii of the cylinders = 2x:3x
And ,
ㅤRatio of the heights of ㅤ"ㅤ"ㅤ= 5x:4x
•°• C.S.A of the first cylinder »
➪ 2 π r h
➪ 2 × 22/7 × 2x × 5x
➪ 44/7 × 10x²
➪ 62.850 x²ㅤㅤ ----------- ( approx )
Now ,
☯︎ C.S.A of the second Cylinder »
➪ 2 π r h
➪ 2 × 22/7 × 3x × 4x
➪ 44/7 × 12x²
➪ 75.425 x² ㅤㅤㅤ---------- ( approx )
•°• Ratio of their C.S.A =
ㅤㅤㅤ➪ 62.850x² / 75.425x²
ㅤㅤㅤ➪ 0.8
ㅤㅤㅤ➪ 8/10
ㅤㅤㅤ➪ 4 / 5
•°• Ratio of their C.S.A = 4:5
ㅤㅤㅤ꧁ ʙʀᴀɪɴʟʏ×ᴋɪᴋɪ ꧂
ㅤㅤㅤ
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