The range of a projectile when fired at angle 75 to the horizontal is 0.5 km. what will be its range when fired at 45 with same speed..please explain properly
pallavisharma9:
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Answered by
119
Hi
horizontal range =u^2sin2Q/g
sin150=1/2
swe get same value
horizontal range =u^2sin2Q/g
sin150=1/2
swe get same value
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Answered by
1
The range of the projectile would be 1.0m when fired at 45°
Explanation:
=
=
=
= = 0.5m
=
=
=
= 1.0m
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