Question

The rate of flow of liquid ina tube of radius r, length l, whose ends are maintained at a pressure difference P is V = (piQPr^(4))/(etal) where eta is coefficient of the viscosity and Q is

Answer 1

The rate of flow of liquid is written as Q

• The r be the radius
• L be the length  and P is the pressure difference.
• Generally the Q is represented as rate of flow of liquid but here it is taken as V
• Therefore V=πQPr⁴/ηl
• As for now V=Q
• Now using the Poiseuille equation for the rate of flow of liquid.
• Which is V=πΔPr⁴/8lη
• Comparing with the above equation of V
• So on comparing we get the value of Q=1/8
• That is the value of Q.

Answer 2

Answer:

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