The rate of reaction of CCl3
CHO + NO CHCl3
+ NO + CO is given by the equation is
Answers
The rate of the given equation is given is equal to rate =k [CCl3CHO] [NO]. The concentration will expressed in mol L^(-1).
The unit of k will expressed in L mol^(-1) s^(-1) due to following reasons:-
- The given reaction is expressed as,
CCl3CHO + NO ---> CHCl3 + NO + CO
- The rate of reaction is given as,
rate =k[CCl3CHO][NO]
- It is given that the concentration is expressed in mol L^(-1)
- As we know that,
Rate = dx/dt = k[CCl3CHO][NO]
- So, k = dx/dt[CCl3CHO][NO]
dx is the concentration expressed in terms of mol L^(-1)
whereas, dt is the time expressed in terms of s^(-1)
- By putting the values we have,
k = mol L^(-1)/s^(-1) × mol L^(-1) × mol L^(-1)
k = L mol^(-1)s^(-1).
- So, The unit of k is expressed as
L mol^(-1)s^(-1)