The ratio in which the line segment joining p (-3,7) and q(7,5) is divided by y-aixs is
Answers
Answered by
1
since the line segment is divided by the y-axis, so we can let the point of division is (h, 0).
or we can directly find the equation of the line as:
(y-Y1) = [(Y2 -Y1)/(X2 - X1)] × (x-X1)
where (X1,Y1) = (-3,7)
(X2,Y2) = (7,5)
Hence after finding the equation of the line,
put the point (h,0) in the equation, to get value of 'h'.
we have put the point (h, 0) because this point lies in this straight line as it is divided through it.
and finally use the formula to find the ratio that is:
(mY2 - nY1)/(m-n) , (mX2 - nX1)/(m-n)= (h,0)
and then find the value of 'm' and 'n'.
so finally you get the line is divided in the ratio m:n.
or we can directly find the equation of the line as:
(y-Y1) = [(Y2 -Y1)/(X2 - X1)] × (x-X1)
where (X1,Y1) = (-3,7)
(X2,Y2) = (7,5)
Hence after finding the equation of the line,
put the point (h,0) in the equation, to get value of 'h'.
we have put the point (h, 0) because this point lies in this straight line as it is divided through it.
and finally use the formula to find the ratio that is:
(mY2 - nY1)/(m-n) , (mX2 - nX1)/(m-n)= (h,0)
and then find the value of 'm' and 'n'.
so finally you get the line is divided in the ratio m:n.
Similar questions