Math, asked by ganeshrajandlawar, 3 months ago

The ratio of present ages of two brothers is 1 : 2 and
5 years back the ratio was 1 : 3. What will be the
ratio of their ages after 5 years




Answers

Answered by piyushsinghshrinet7
72

Answer:

3:5

Step-by-step explanation:

x-5/2x-5 = 1/3

3x-15 = 2x-5

3x-15+5 = 2x

3x - 10 = 2x

3x-2x = 10

x = 10

2x = 20

After 5 years

x+5/2x + 5

10+5/20+5

15/25

3/5

3:5 Answer.

Answered by ShírIey
98

AnswEr :

❍ Given that, the ratio of present ages of two brothers is 1: 2. So, let's say that the present ages of the two brothers be x and 2x respectively.

⭒ By Given C O N D I T I O N :

  • Five years back, the ratio of their ages (both brother's ages) was 1: 3.

Therefore,

Five years ago their ages —

  • Younger brother = (x – 5)
  • Elder brother = (2x – 5)

⠀⠀⠀

Now,

⠀⠀⠀⠀

\dashrightarrow\sf \bigg\{\dfrac{x - 5}{2x - 5}\bigg\} = \bigg\{\dfrac{1}{3}\bigg \}  \\  \\\\\dashrightarrow\sf 3\Big\{x - 5\Big\} = \Big\{2x - 5\Big\} \\ \\ \ \\\dashrightarrow\sf 3x - 15 = 2x - 5\\\ \\   \\\dashrightarrow\sf  3x - 2x = - 5 + 15\\\  \\ \ \\\dashrightarrow\underline{\boxed{\frak{\pmb{\pink{x = 10 }}}}}\;\bigstar

Hence,

  • Present ages of both brother are, x = 10 years

  • 2x = 2(10) = 20 years

⠀⠀⠀⠀

\therefore{\underline{\textsf{Present~ages~of~two~brothers~are~\textbf{10 years and 20 years}.}}}

⠀⠀⠀

\rule{300px}{.3ex}

R A T I O :

  • After five years the ratio their ages will be —

:\implies\sf \dfrac{10 + 5}{20 + 5} \\\\\\:\implies\sf \cancel\dfrac{15}{25} \\ \\ \\:\implies{\boxed{\underline{\frak{\purple{\dfrac{3}{5}}}}}}\;\bigstar

⠀⠀⠀⠀

\therefore{\underline{\textsf{Hence,~the~required~ratio~of~their~ages~is~ \textbf{3:5}.}}}⠀⠀⠀⠀

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