Question

The ratio of rate of diffusion of CH4 and O3, under
similar conditions of temperature and pressure is
((1) 1:3
(2) 3:2
(3) √2:1
(4) √3:1​

Answer 1

Answer:

4) (3)^1/2 : 1

Explanation:

Rate of Diffusion 1 / Rate of Diffusion 2 = (Molecular mass 2 / Molecular Mass 1)^1/2

Answer 2

The answer is option (4) √3:1

GIVEN

Gases; CH₄ and O₃

TO FIND

The ratio of rate of diffusion under similar temperature and pressure.

SOLUTION

We can simply solve the above problem as follows;

According to Graham's law of diffusion: The rate of diffusion of gas is inversely proportional to its molecular weight.

$\frac{r1}{r2} = \sqrt{ \frac{m2}{m1} }$

Where,

r1 and r2 = rate of diffusion of CH₄ and O₃ respectively.

And,

m1 = molecular weight of CH₄ = 16 grams

m₂ = Molecular weight of O₃ = 48 grams

Putting the values in the above formula we get;

$\frac{r1}{r2} = \sqrt{ \frac{48}{16} } = \frac{\sqrt{3} }{1 }$

r1 : r2 = √3 : 1

Hence, The answer is option (4) √3:1

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