Question

The ratio of Tb/Tc is found....

Answer 1

Answer : The ratio of Tb : Tc is, 28 : 8

Explanation :

Boyle Temperature : It is the temperature in which the second virial coefficient, becomes zero.

The formula of Boyle temperature is,

$T_b=\frac{a}{Rb}$         ...............(1)

where,

$T_b$ = Boyle temperature

'a' and 'b' are the vander waals constant

R = universal gas constant

Critical temperature : It is the temperature at and above which vapor of the substance cannot be liquefied.

The formula of Critical temperature is,

$T_c=\frac{8a}{27Rb}$                ....................(2)

where,

$T_c$ = Critical temperature

'a' and 'b' are the vander waals constant

R = universal gas constant

Now taking ratio of equation (1) and (2), we get

$\frac{T_b}{T_c}=\frac{\frac{a}{Rb}}{\frac{8a}{27Rb}}\\\\\frac{T_b}{T_c}=\frac{27}{8}$

Therefore, the ratio of Tb : Tc is, 28 : 8

Answer 2

Explanation:

the ratio of this question is 27 ratio 8