the ratio of the age of a and b is 9:4 three years ago the ratio of their age was 3:1 find the present age
Answers
Answered by
3
let the ratios be x
a=9x
b=4x
a/q,
9x-3/4x-3=3/1
12x-9=9x-3
12x-9x=-3+9
3x=6
x=2years
then, a=18years
b=8years
am I right? comment
a=9x
b=4x
a/q,
9x-3/4x-3=3/1
12x-9=9x-3
12x-9x=-3+9
3x=6
x=2years
then, a=18years
b=8years
am I right? comment
Answered by
0
a/b=9/4
let , the common multiple be x
therefore age of a=9x
age of b=4x
3years ago
the age of a=9x-3
age of b=4x-3
but 3 years ago the ratio is
3/1, therefore
3/1= 9x-3/4x-3
9x-3=12x-9
9-3=12x-9x
6=3x
x=2
the present age of a=9x=18years
present age of b=4x=8years
let , the common multiple be x
therefore age of a=9x
age of b=4x
3years ago
the age of a=9x-3
age of b=4x-3
but 3 years ago the ratio is
3/1, therefore
3/1= 9x-3/4x-3
9x-3=12x-9
9-3=12x-9x
6=3x
x=2
the present age of a=9x=18years
present age of b=4x=8years
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