The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
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Answered by
12
The answer is 21 : 22.
Step-by-step solution:-
Let the number of boys = 7k
and the number of girls = 8k
Due to increase in percentage,
Number of boys = 7k x 120/100 = 42k/5
Number of girls = 8k x 110/100 = 44k/5
Hence,the required ratio = (42k/5 : 44k/5) = 21:22
Alternatively,solution:-
Let the number of boys as 70 and girls as 80 .
=> Effect of rise of percentage on:-
Boys = 20% rise = 70 + 70× 20/100 = 70 +14 = 84
Girls = 10% rise =80 + 80 × 10/100 = 80 +8 = 88
Hence,the new ratio = 84:88 = 21 : 22
Step-by-step solution:-
Let the number of boys = 7k
and the number of girls = 8k
Due to increase in percentage,
Number of boys = 7k x 120/100 = 42k/5
Number of girls = 8k x 110/100 = 44k/5
Hence,the required ratio = (42k/5 : 44k/5) = 21:22
Alternatively,solution:-
Let the number of boys as 70 and girls as 80 .
=> Effect of rise of percentage on:-
Boys = 20% rise = 70 + 70× 20/100 = 70 +14 = 84
Girls = 10% rise =80 + 80 × 10/100 = 80 +8 = 88
Hence,the new ratio = 84:88 = 21 : 22
Answered by
4
Let the number of boys be 7x and girls be 8x.
The percentage increase in the number of boys and girls be 20% and 10% respectively.
Increased number of boys = 20% of 7x
→ 120/100×7x
→ 42x/5
Increased number of girls = 10% of 8x
→ 110/100×8x
→ 44x/5
New ratio = 42x/5 : 44x/5
→ 42x : 44x
→ 21:22
The percentage increase in the number of boys and girls be 20% and 10% respectively.
Increased number of boys = 20% of 7x
→ 120/100×7x
→ 42x/5
Increased number of girls = 10% of 8x
→ 110/100×8x
→ 44x/5
New ratio = 42x/5 : 44x/5
→ 42x : 44x
→ 21:22
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