Question

the ratio of the number of boys and girls in a school is 3:2. If 20% of the boys and 30% of the girls are scholarship holders, the percentage of the students who are not scholarship holder is??​

Answer 1

$\huge \underline \mathbb {SOLUTION:-}$

AnsWer:

• The percentage of the students who are not scholarship holder is 76%.

Given:

• The ratio of the number of boys and girls in a school is 3:2. If 20% of the boys and 30% of the girls are scholarship holders.

Need To Find:

• The students who are not scholarship holder = ?

Explanation:

Let the number of boys and girls be 3x and 2x.

Number of those who are not scholarship holder:

$= (80\% \: of \: 3x \: + \: 70\% \: of \: 2x)$

$= \frac{12x}{5} + \frac{7x}{5}$

$= \frac{19x}{5}$

∴ Required percentage

$= ( \frac{19x}{5} \times \frac{1}{5x} \times 100)\%$

$= 76\%$

• Hence, the percentage of the students who are not scholarship holder is 76%.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

Answer 2

Answer:

Step-by-step explanation:

Let there be 100 students.

Then number of boys =

3/5×100=60

Number of girls = 2/5*100=40

Total scholarship holders =20 % of 60 + 30 % of 40=

20/100×60+ 30/100×40

= 12+12

=24

Number of students without scholarship =100−24=76

∴% of students without scholarship =

​ 76/×100=76 %