Math, asked by ankitjha226pb71px, 1 year ago

The ratio of the present ages of rohit and mohit is 9:10.if 6 years ago the sum their ages was 45 years. Then find the present ages of rohit

Answers

Answered by Anonymous
5
hey!!!

the ratio of the present ages of rohit and mohit is 9:10.

let their present age be 9x and 10x

6 yrs ago, the sum of their age was 45

therefore 9x - 6 + 10x - 6 = 45 yrs
>> 19x - 12 = 45 yrs
>> 19x = 45 + 12
>> 19x = 57
>> x = 57/19
>> x = 3

hence, present age of Rohit = 9x = 9 × 3 = 27 yrs

present age of Mohit = 10x = 10 × 3 = 30 yrs

cheers!!!
Similar questions