Question

The reaction conditions leading to the best yields of C₂H₅Cl
are :
(a) C₂H₆ (excess) + Cl₂ □(→┴UV Light )
(b) C₂H₆ + Cl₂ □(→┴dark )
(c) C₂H₆ + Cl₂ (excess) □(→┴UV Light )
(d) C₂H₆ + Cl₂ □(→┴UV Light )

Answer 1

Answer:

The reaction conditions leading to the best yields of C₂H₅Cl

are :

(a) C₂H₆ (excess) + Cl₂ □(→┴UV Light )

(b) C₂H₆ + Cl₂ □(→┴dark )

(c) C₂H₆ + Cl₂ (excess) □(→┴UV Light )

(d) C₂H₆ + Cl₂ □(→┴UV Light )

Answer 2

C₂H₆ (excess) + Cl₂ □(→┴UV Light ) is the reaction.

Explanation:

• Ethane is the 2 carbon alkane and the reagent is chlorine.

• In presence of sunlight, the chlorine forms free radicles i.e Cl.

• This free radicle attacks the ethane and replaces hydrogen radicle to form ethyl chloride and hydrogen chloride.

• This probability of the chloride radicle attacking the ethane increases by taking excess of it.

• This reaction follows the free radicle substitution process.

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