Science, asked by ayushkashyap960, 1 year ago

The reaction of m-bromoanisole with NaNH2 in liquid ammonia yields :–

Answers

Answered by Anonymous
4
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The reaction of m-bromoanisole with NaNH2 in liquid ammonia yields m-aminoanisole.

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Answered by anjaliom1122
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Complete Question :

The reaction of m-bromoanisole with NaNH2 in liquid ammonia yields :– (a) o-aminoanisole (b) m-aminoanisole

(c) p-aminoanisole (d) a mixture of o-, m- and p- aminoanisole

Answer:

(b) m-aminoanisole

The reaction of m-bromoanisole with NaNH2 in liquid ammonia yields is m-aminoanisole

Explanation:

m-aminoanisole is an organic compound with the formula CH^{3}OC^{6}H^{4}NH^{2}. A clear light yellow or amber liquid, commercial samples may appear brown due to air oxidation. It is one of three isomers of the methoxy-containing aniline derivative. Because it dissociates to produce the amide species, sodium amide would act as a base in liquid ammonia. Because this amide ion has a proclivity to accept proton, it is a base.

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