the rectangle has length 15 cm and breadth 45 CM square has its sides 48 CM which has more area and by how much solve it with
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area of rectangle= l x b
l=15 cm
b=45 cm
15 x 14 =210 square cm
area of square =a x a
a=48
48 x 48 = 2304 square cm
hence the area of square is more by 2094 cm square
l=15 cm
b=45 cm
15 x 14 =210 square cm
area of square =a x a
a=48
48 x 48 = 2304 square cm
hence the area of square is more by 2094 cm square
Answered by
1
Heya,
Here is the answer:-
Given:-
》Rectangle:-
Length = 15cm
Breadth = 45cm
》Square:-
Side = 48cm
Area of rectangle = l × b
Area of rectangle = 15 × 45
Area of rectangle = 675cm^2
Area of square = s^2
Area of square = 48^2
Area of square = 2304cm^2
Therefore,
Area of square is greater than the area of rectangle.
=> 2304 - 675
=> 1629
Area of square is greater than the area of rectangle by 1629cm^2
Hope my answer helps you :)
Regards,
Shobana
Here is the answer:-
Given:-
》Rectangle:-
Length = 15cm
Breadth = 45cm
》Square:-
Side = 48cm
Area of rectangle = l × b
Area of rectangle = 15 × 45
Area of rectangle = 675cm^2
Area of square = s^2
Area of square = 48^2
Area of square = 2304cm^2
Therefore,
Area of square is greater than the area of rectangle.
=> 2304 - 675
=> 1629
Area of square is greater than the area of rectangle by 1629cm^2
Hope my answer helps you :)
Regards,
Shobana
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