Question

The refractive indexes of four substances P, Q, R and S are 1.77, 1.50, 2.42 and 1.31 respectively. When light travelling in air is incident on these substances at equal angles, the angle of refraction will be the maximum in
(a) substance P
(b) substance Q
(c) substance R
(d) substance S

Answer 1

The refractive indexes of four substances P, Q, R and S are 1.77, 1.50, 2.42 and 1.31 respectively. When light travelling in air is incident on these substances at equal angles, the angle of refraction will be the maximum in substance S

Explanation:

From the law of refraction, we know that, refractive index, n = $\frac{sini}{sinr}$

For all the cases, the sin i value remains the same. But in order to have a maximum angle of refraction, the refractive index must be least. So, in this case, among four of the substances, substance S has minimum refractive index value i.e., 1.31. Hence, when the light traveling in air is incident on these substances at equal angles, the angle of refraction will be maximum in substance S.

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Answer 2

Answer: It will be Option (C).

Explanation: According to question, the maximum refraction will occur in substance R as it has high refractive index and we know if refractive index is high means density is high and if density is high then the light needs more time to cross the hurdle. So, Correct Option is (C) Substance R.