Question

The remainder when the following polynomial P(X) is divided by x-1​

Answer 1

Ans:- Given:-

p(x) = x³ - 8x²+21x-18

g(x) = (x-1)

To find, Remainder

Solution:-

=> x - 1 = 0

=> x = 1

Now, put the value of x in p(x) we get,

=> p(1) = (1)³-8(1)²+21(1)-18

=> p(1) = 1 - 8 + 21 - 18

=> p(1) = 22 - 26

=> p(1) = -4

hence remainder is (-4)

here is your answer

hope it will help you

Answer 2

Answer:

Remainder will be 4.

Step-by-step explanation:

x^3/x will be x^2 which will become quotient and would be multiplied by x-1,

and will result in x^3 -x.

Next, -8x^2 will be divided by x, as in the first case, and will result into -8x will be written in quotient again,

and the same (-8x) will not get multiplied by x-1 and will result into -8x^2 +8x.

Same with the remaining and you'll end up with remainder 4 at the end.

Hope you get the method.