The remainder when x4-y4 is divided by x+y is
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Answered by
22
Let p(x)= x4-y4
When p(x) is divided by x+y then the remainder will be p(-y) [x+y=0, then x=(-y)]
i.e p(-y)= (-y)4-y4
= y4-y4
=0
Therefore, the remainder when x4-y4 is divided b x+y is 0!
Hope this was helpful.
When p(x) is divided by x+y then the remainder will be p(-y) [x+y=0, then x=(-y)]
i.e p(-y)= (-y)4-y4
= y4-y4
=0
Therefore, the remainder when x4-y4 is divided b x+y is 0!
Hope this was helpful.
Answered by
8
p(x)= x4-y4
when p(x) divided by x+y we get 0
quotient = 4
when p(x) divided by x+y we get 0
quotient = 4
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