Question

The resistance of 1 n solution of acetic acid is 250 ohm, when measured in a cell of cell constant 1.15 cm1. The equivalent conductance (in ohm1cm2eq1) of 1 n acetic acid is:

Answer 1

Explanation:- 

We have Specific conductance,

k=Cell constant/resistance 
=1.15/250 

=23/5000 mho/m 

Also we have, 
Equivalent conductance = k*1000/N 

= (23/5000)*1000 

=4.6

Answer 2

Answer : The equivalent conductance is, $4.6\Omega^{-1}cm^2eq^{-1}$

Explanation:

First we have to calculate the conductivity of the cell.

Formula used : $K=\frac{\text{Cell constant}}{R}$

where,

K = conductivity = ?

Cell constant = $1.15cm^{-1}$

R = Resistance = 250 ohm

Now put all the values in this formula, we get the conductivity of the cell.

$K=\frac{1.15cm^{-1}}{250\Omega}$

Now we have to calculate the equivalent conductance.

Formula used : $\Lambda_{eq}=\frac{K\times 1000}{C}$

where,

$\Lambda_{eq}$ = equivalent conductance = ?

C = concentration = 1 N

Now put all the given values in the above formula, we get the equivalent conductance.

$\Lambda_{eq}=\frac{(\frac{1.15cm^{-1}}{250\Omega})\times 1000}{1N}=4.6\Omega^{-1}cm^2eq^{-1}$

Therefore, the equivalent conductance is, $4.6\Omega^{-1}cm^2eq^{-1}$