The resistance of 1 n solution of acetic acid is 250 ohm, when measured in a cell of cell constant 1.15 cm1. The equivalent conductance (in ohm1cm2eq1) of 1 n acetic acid is:
Answers
Answered by
21
Explanation:-
We have Specific conductance,
k=Cell constant/resistance
=1.15/250
=23/5000 mho/m
Also we have,
Equivalent conductance = k*1000/N
= (23/5000)*1000
=4.6
We have Specific conductance,
k=Cell constant/resistance
=1.15/250
=23/5000 mho/m
Also we have,
Equivalent conductance = k*1000/N
= (23/5000)*1000
=4.6
Answered by
15
Answer : The equivalent conductance is,
Explanation:
First we have to calculate the conductivity of the cell.
Formula used :
where,
K = conductivity = ?
Cell constant =
R = Resistance = 250 ohm
Now put all the values in this formula, we get the conductivity of the cell.
Now we have to calculate the equivalent conductance.
Formula used :
where,
= equivalent conductance = ?
C = concentration = 1 N
Now put all the given values in the above formula, we get the equivalent conductance.
Therefore, the equivalent conductance is,
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