Chemistry, asked by hetmali108, 6 months ago

The resistance of a column having diameter 1.0 cm and the length 50 cm containing solution

of 0.05 mol L1- NaOH is 5.55 X 103 ohm, then calculate its resistivity, conductivity and molar

conductivity​

Answers

Answered by mangalasingh00978
2

Explanation:

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Answered by NITESH761
0

Explanation:

\sf Area(a) = πr^2=3.14×(0.5)^2

\sf = 0.785 \: cm^2 = 0.785×10^{-4}\:m^2

  • l = 50 cm = 0.5 m

\sf R = \rho \dfrac{l}{a}

\sf \rho = \dfrac{5.55×10^3\: ohm × 0.785 \: cm^2}{50 \: cm}

\sf \rho = 87.135 \: ohm \: cm

\sf \kappa = \dfrac{1}{\rho}

\sf  = \bigg( \dfrac{1}{87.135} \bigg) S \: cm^{-1} =0.01148 \: S \: cm^{-1}

\sf \Lambda _m = \dfrac{\kappa ×1000}{M} \: cm^3 \: L^{-1}

 \sf= \dfrac{0.01148 \: S \: cm^{-1} × 1000 \: cm^3 \: L^{-1}}{0.05 \: mol \: L^{-1}}

\sf = 229.6 \: S \: cm^2 \: mol^{-1}

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