Question

The resistance of a conductivity cell containing 0.001m kcl solution at 298k is 1500 ohm. Calculate cell constant is conducticity of 0.001m kcl solution at 298 k is 0.146*10^-3 s cm^-1

Answer 1

Hey !!

Conductivity (κ) = 1 / Resistance (R) × Cell Constant

κ = 0.146 × 10⁻³ S cm⁻¹ , R = 1500 Ω

       0.146 × 10⁻³ S cm⁻¹ = 1 / 1500 Ω × Cell constant

∴ Cell constant = 0.146 × 10⁻³ S cm⁻¹ × 1500 Ω

           = 219 × 10⁻³ cm⁻¹

           = 0.219 cm⁻¹

Hope it helps you !!

Answer 2

R=1500 Ω (Resistance)

k=1.46×10^−4 Scm^−1 (Conductivity) 

T=298 K

We will use the formula, k=Gx

where k is conductivity

G is 1/R

x is cell constant

1.46×10^−4=1/15001×x

1.46×10^−4×1500=x

0.219 cm^−1=x

The cell constant is 0.219 cm−1