Question

The resultant of two equal forces is double of either of the forces the angle between them is

Answer 1

Answer:

this solution will help you definitely

Answer 2

Answer:

The resultant of two equal forces is double of either of the forces the angle between them is $0^\circ$

Explanation:

Resultant of two equal forces are calculated as,

$R=\sqrt{F^2+F^2+2F.F.cos\theta}\\R=\sqrt{2F^2+2F^2cos\theta}\\R=\sqrt{2F^2(1+cos\theta)}\\R=F\sqrt{2(1+cos\theta)}$

The Resultant of two equal forces are double of either of the forces,

$2F=F\sqrt{2(1+cos\theta)}$

Squaring both sides,

$4F^2=2F^2(1+cos\theta)}\\2=1+cos\theta\\cos\theta=1\\\theta=0^\circ$