the resultant of two resistance which are connected in parallel is 80 ohms. If one resistance value is 40 ohms.find the value of secured resistance.
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1/R = 1/R1 + 1/R2
1/R2 = 1/R - 1/R1
1/R2= 1/80 - 1/40
1/R2= 2+1/80
R2 = 80/3
1/R2 = 1/R - 1/R1
1/R2= 1/80 - 1/40
1/R2= 2+1/80
R2 = 80/3
mani9784:
i have done reciprocal of it
oh sorry , i have done that one wrong
yes u had correct it
that will be 80 answer
ch*****
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